# Binary and Hex Tables and Illustrations

Powers of 2 and 16:

Conversion Table:

Inverse Conversion Table: follow link

Notation:

Convert hex, binary, decimal; signed and unsigned, Online:

Example of Binary to Decimal conversion:

Example of Hex to Decimal conversion:

Example of Byte-by-Byte Hex to Decimal conversion (for two-byte, big endian number):

Signed Integers: 2's complement for 16-bit data:

Standard OBD-II PIDs:

en.wikipedia.org/wiki/OBD-II_PI…

Note on the first byte of OBD request and response:

Request: mode $01 to $0A

Response: to indicate valid response, replace the first ‘0’ in the mode with ‘4’, or, equivalently, set to $40 + mode.

Example: for mode $01, calculate $40+$01 = 64 (decimal) + 1 (decimal) = 65 (decimal) = $41

J1979 DA Apr 2021:

J1979 DA Apr2002 public reference:

law.resource.org/pub/us/cfr/ibr….pdf

Standard ASCII:

Extended ASCII:

Most/Least Significant Bits:

Byte Endianness:

Example of Canonical Hex + ASCII Display:

Online Canonical Hex + ASCII Display: hex-works.com/eng

**Raw Mode 1 and 6 data, ELM327 interface for Subaru EJ25:**

`>atz`

`ELM327 v1.3a`

`>atrv`

`12.4V`

`>atsp0`

`OK`

`>0100`

`SEARCHING...`

`41 00 BE 3F E8 13`

`>010c`

`41 0C 00 00`

`>010c`

`41 0C 0E 96`

`>0600`

`46 00 C0 00 00 01`

`>063d`

`00A `

`0: 46 3D 98 FE 00 69 `

`1: 80 00 0D 8A 00 00 00`

`>0641`

`00A `

`0: 46 41 9B 14 00 1F `

`1: …`

`>0671`

`052 `

`0: 46 71 9E 17 27 12 `

`1: 00 00 29 AD 71 9F 0B `

`2: … `

`3: A1 0B … `

`4: 32 71 B0 17 06 9A 00 `

`5: 5D FF FF 71 B5 0B 01 `

`6: 27 00 31 FF FF 71 B6 `

`7: 0B … FF FF `

`8: 71 B8 0B 03 7E 00 00 `

`9: 32 C8 71 B9 31 0A 62 `

`A: … BA 31 `

`B: 0B A…`

**Mode $06 response format in ELM 327 (received over CAN bus):**

46 [ 1-byte MID, 1-byte TID, 1-byte SID, 2-byte Measurement, 2-byte Minimum, 2-byte Maximum]

- MID – look up in SI
- TID – look up in SI
- SID – look up in J1979 DA, Appendix E (pp. 78-94, see link above)
- determine signed or unsigned
- determine scale
- determine offset

**Practice questions for Module 1:**

- In one episode of animated science fiction sitcom Futurama, robot Bender runs away when binary number … is shown reflected in a mirror of a haunted castle. Why is that?
- If PCM replied
`41 00 BE 3F E8 13`

to ELM327 command`0100`

, is Coolant Temperature PID available? - What is ELM327 command to show Coolant Temperature PID?
- If the actual coolant temperature is 76 deg Celsius, what do you expect PCM's reply to the previous command be?

**Practice questions for Module 2:**

- Interpret the following hex numbers as 16-bit signed (2's complement) integers:
- FFFFh
- 8000h
- 7FFFh
- F000h

- Which 16-bit hex number, if interpreted as 2's complement, corresponds to -10 (decimal)?
- Which 8-bit hex number, if interpreted as 2's complement, corresponds to -10 (decimal)?
- For commands discussed during the presentation, reproduce values seen on the scantool (31 Ohm for command 0641, and 0.11 inH20 for command 063d).
- For response to command 0671 (see above), determine TIDs, SIDs, Measurements, Minimums, Maximums. Are all measurements within valid ranges?

Dmitriy, Thanks for the class tonight. The only way I will retain this stuff is to practice it so here's my answers to your questions. I'll put them here for discussion and to see if I got them right. - Bender saw the number … in a mirror so the mirror image would be … Putting that number in the binary converter returns a value of 666. Sign of the devil - Yes coolant pid…

Good job, Bob, you are ready for Module 2! For question 4, what would be the full reply from the PCM? (Bob, I am sure you can answer this one, so why don't someone else gives it a try?)

Also, in your rpm example isn't the formula 256*A+B/4 or 3584+150=3734 divided by 4 = 933.5 rpm?

This is the formula: diag.net/file/f6a9w33bo… The order of calculations matters, you have to compute 256*A+B first, so in the calculator you have to punch in (256*A+B) / 4 I should have mentioned that in the presentation. Thanks for making it better! The final answer is 3734 / 4 = 933.5 rpm, correct.

I have some answers to Module 2 questions. Here goes, - (FFFFh = -1) (8000h = -32768) (7FFFh = 32767) (F000h = -4096) - FFF6 - F6 - 31 ohm = 1F .11 H2O = 6D It's going to take me a little longer for the last question. How are my answers so far? Bob